Statics · Module 9 of 11 · Advanced
Center of Gravity and Centroid
Centroids locate where distributed geometry can be balanced or replaced.
Readiness check
From earlier modules and prerequisite math. Tick only what you can do closed-notes.
- Compute a weighted average (grades, prices, anything).
- Find areas of rectangles, triangles, and circles instantly.
- Set up a coordinate system and stick to it for a whole problem.
- Explain why a distributed load can be replaced by one force (Module 4).
- Evaluate a simple definite integral (for the integration sections).
The core idea
A centroid is an area-weighted average position. Nothing more.
x̄ = Σx̄iAi / ΣAiComposite method: split the shape into simple pieces, take each piece's known centroid, weight by its area, divide by total area. Holes are pieces with negative area. The same recipe works for lines, volumes, and masses.
The method
Declare the origin and axes; mark them on the sketch.
Split into rectangles, triangles, circles; holes are negative.
Mark each piece's own centroid and coordinates.
Build the ΣxA table. Always the table.
Worked example: centroid of an L-shaped plate
An L-shaped plate: a horizontal base 4 m wide and 1 m tall, plus a vertical leg 1 m wide and 3 m tall sitting on the base's left end. Locate the centroid from the bottom-left corner.
- ProblemLocate the centroid of the plate in Figure 1.
- Given / findThe two rectangles above. Find (x̄, ȳ) from the corner O.
- AssumptionsUniform thickness and density, so the area centroid is also the center of gravity.
- ModelFigure 2: piece 1 (base): A₁ = 4 m², centroid (2, 0.5). Piece 2 (leg): A₂ = 3 m², centroid (0.5, 2.5). Tabulate. Always tabulate.
- Equationsx̄ = (ΣxiAi)/(ΣAi) ȳ = (ΣyiAi)/(ΣAi)
- SolveΣA = 7 m². x̄ = (4×2 + 3×0.5)/7 = (8 + 1.5)/7 = 1.36 m. ȳ = (4×0.5 + 3×2.5)/7 = (2 + 7.5)/7 = 1.36 m.
- CheckThe centroid must sit between the two piece centroids, pulled toward the bigger piece (the base): 1.36 lies between 0.5 and 2 in x, between 0.5 and 2.5 in y, closer to the base values. In an L it can even lie outside the material, plausible here.
- ConclusionHang the plate from this point and it balances level. For a crane lift of a real L-bracket, the sling must pass through the vertical line at x̄ = 1.36 m or the part will rotate when lifted.
Misconceptions and diagnostics
| Mistake | Symptom | Diagnostic question | Correction |
|---|---|---|---|
| Averaging centroids without area weights | x̄ = (2 + 0.5)/2 = 1.25 in the example above | "Did every coordinate get multiplied by its own area?" | The bigger piece pulls harder. Always build the ΣxA table. |
| Wrong local centroid for a triangle | Distributed-load and composite answers consistently off | "Is the triangle centroid at h/2 or h/3?" | h/3 from the base (2h/3 from the apex). Memorize triangle, semicircle (4r/3π), quarter circle. |
| Forgetting holes subtract | Centroid biased toward the cut-out | "Is any region in my table actually empty?" | Enter holes with negative area and their own centroid; the algebra handles the rest. |
| Switching reference origin mid-table | Coordinates inconsistent; answer lands outside the part absurdly | "Are all x values measured from the same origin?" | Declare the origin in step 1, mark it on the sketch, never move it. |
Practice ladder
A T-shape: flange 6 × 1 on top of a web 1 × 4 (web centered). Find ȳ from the bottom.
Show answer
Web: A = 4, ȳ = 2. Flange: A = 6, ȳ = 4.5. ȳ = (4×2 + 6×4.5)/10 = 35/10 = 3.5. Pulled toward the heavy flange.
A 200 × 100 mm rectangular plate has a 50 mm diameter hole centered at (150, 50) mm. Find x̄.
Show answer
Plate: A = 20 000, x̄ = 100. Hole: A = −1963.5, x̄ = 150. x̄ = (2 000 000 − 294 524)/18 036.5 = 94.6 mm. Shifted away from the hole.
Use the centroid idea to re-derive the Module 4 fact: a triangular load from 0 to w₀ over length L is equivalent to ½w₀L acting at 2L/3 from the zero end.
Show answer
The loading diagram is a triangle of "area" ½w₀L (total force). Its centroid lies L/3 from the heavy end, which is 2L/3 from the zero end. Resultant magnitude = area, location = centroid: one idea, two chapters connected.
Take a real flat object with an irregular shape (bracket, phone stand, cardboard cutout). Predict its balance point by composite calculation, then find it experimentally (balance on a pencil edge two ways). Report predicted versus measured.
What good work looks like
A dimensioned sketch, the composite table, predicted (x̄, ȳ), the measured point from two balance lines, and a percent deviation with one honest error source (thickness variation, rounded corners).
Working with AI, and proving it yourself
Use AI as an examiner, not a solver
Portfolio task
Model a composite part (your Level 4 object or a CAD part) and produce a one-page centroid report: dimensioned sketch, composite table, result, experimental or CAD verification, and one sentence on why the location matters (lifting, stability, or balance).
Retrieval and spaced review
Closed notes. Answer out loud, then reveal.
1. Distinguish centroid, center of mass, and center of gravity.
Centroid: geometric average of area or volume. Center of mass: density-weighted. Center of gravity: weight-weighted. They coincide for uniform density in uniform gravity.
2. Write the composite-body centroid formula.
x̄ = Σx̄iAi/ΣAi (same pattern for ȳ, and with V or W as weights for volumes and bodies). Holes enter with negative area.
3. Local centroids: triangle, semicircle?
Triangle: h/3 from the base. Semicircle: 4r/(3π) ≈ 0.424r from the flat edge, on the symmetry axis.
4. Why does a distributed load's resultant act at the loading diagram's centroid?
Equivalence requires equal moment: ∫x·w(x)dx = x̄·∫w(x)dx, which is exactly the centroid definition of the w-diagram's area.
5. What symmetry shortcut applies to centroids?
The centroid lies on every axis of symmetry; two axes pin it down with zero computation.
Textbook mapping
| Item | Mapping |
|---|---|
| Main textbook | R.C. Hibbeler, Engineering Mechanics: Statics, Chapter 9, Center of Gravity and Centroid |
| Core sections | 9.1 Center of Gravity, Center of Mass, and the Centroid of a Body · 9.2 Composite Bodies (the workhorse) |
| Recommended problems | Fundamental Problems F9-1 onward (partial solutions in the back). Do composite problems until the table format is automatic. |
| Skip on first pass | 9.3 Pappus and Guldinus, 9.4 General Distributed Loading, 9.5 Fluid Pressure; return before Fluid Mechanics for 9.5. |
| Read next | Chapter 10, sections 10.1 to 10.4 before opening Module 10. |