Manufacturing · Chapter 2 of 10 · Beginner
Metal Casting
Pour liquid metal into a mould and let it freeze into shape. Simple in principle, but the metal shrinks as it solidifies, and managing that shrinkage is what separates a sound casting from a scrap one.
Readiness check
This chapter uses geometry and a little fluid flow. Tick only what you can do closed-notes.
- Compute volume and surface area of simple shapes.
- Recall that metals shrink on solidifying.
- Use Bernoulli's v = √(2gh) for a falling stream.
- Apply continuity Q = Av.
- Square and take square roots.
The core idea
A casting solidifies from its surfaces inward at a rate set by how much surface it has per unit volume, and it shrinks as it freezes, so the last metal to solidify must be fed from a reservoir.
ts = Cm(V/A)²riser solidifies last: (V/A)riser > (V/A)castingvgate = √(2gh)Heat leaves through the mould walls, so a thick, compact region (high V/A) freezes slowly and a thin one quickly. Chvorinov's rule turns this into a time. Because metal contracts on solidifying, the slowest-freezing spot draws liquid from wherever it can; the founder's job is to make that a sacrificial riser, not a hole in the part. The gating system must also fill the mould fast and smoothly before anything freezes.
The skills, taught in order
Casting is solidification managed by geometry and flow. Five skills cover freezing, Chvorinov's rule, risers, gating, and the process choices.
2.1 Solidification and shrinkage
Molten metal cools, nucleates crystals, and grows them into grains as it freezes, releasing latent heat. It contracts in three stages, and each must be allowed for.
| Stage | What contracts | Handled by |
|---|---|---|
| Liquid contraction | liquid cooling to the freezing point | riser feeding |
| Solidification shrinkage | the liquid-to-solid change (the largest) | riser feeding |
| Solid contraction | solid cooling to room temperature | pattern shrinkage allowance |
2.2 Chvorinov's rule
Solidification time scales with the square of the volume-to-surface-area ratio: ts = Cm(V/A)², where Cm is the mould constant. A sphere (lowest surface per volume) freezes slowest; a thin plate fastest. The ratio V/A, the modulus, is the single most useful number in casting design.
2.3 Risers and feeding
A riser is a reservoir of liquid that feeds the casting's shrinkage. For it to work, it must freeze after the casting, so it needs a larger modulus: (V/A)riser > (V/A)casting. Good design promotes directional solidification, freezing toward the riser so shrinkage ends up in the sacrificial metal, which is cut off.
2.4 Gating and fluidity
The gating system (pouring basin, sprue, runner, gate) delivers metal to the cavity. The velocity at the gate follows Bernoulli, v = √(2gh) from the sprue height h, and continuity Q = Av sets the fill time. The metal must stay fluid long enough to fill thin sections, a property called fluidity, before it freezes.
2.5 Casting processes
Processes trade detail, finish, and cost against volume.
| Process | Finish and tolerance | Volume |
|---|---|---|
| Sand casting | rough, loose | one-off to high; any size |
| Investment casting | excellent, fine detail | low to medium; complex shapes |
| Die casting | good, smooth | high; non-ferrous, fast |
| Permanent mould | good | medium; reusable metal mould |
Engineering connection: engine blocks, pump housings, turbine blades (investment), and countless brackets begin as castings; the modulus idea also guides where defects hide.
Worked example 1: sizing a riser
A casting has a modulus V/A = 1.5 cm in a sand mould with constant Cm = 2.0 min/cm². Find its solidification time, then size a cylindrical riser (height equal to diameter, all surfaces cooling) that solidifies at least 25% longer.
- ProblemFind the casting's solidification time and size the riser in Figure 1.
- Given / find(V/A)cast = 1.5 cm, Cm = 2.0 min/cm², riser t must be ≥ 1.25 tcast, cylinder H = D. Find tcast and the riser diameter.
- AssumptionsSame mould constant for casting and riser; all riser surfaces lose heat; Chvorinov's rule applies.
- ModelChvorinov's rule for the casting time, then invert it for the required riser modulus and convert to a diameter via V/A = D/6 for an H = D cylinder.
- Equationsts = Cm(V/A)² (V/A)riser = √(triser/Cm) V/A = D/6 (H = D cylinder)
- Solvetcast = 2.0(1.5)² = 4.5 min. Required triser = 1.25 × 4.5 = 5.625 min, so (V/A)riser = √(5.625/2.0) = 1.677 cm. With V/A = D/6, D = 6 × 1.677 = 10.1 cm (H ≈ 10 cm).
- CheckThe riser modulus (1.68 cm) exceeds the casting's (1.5 cm), as it must to freeze later. A 10 cm riser on a casting of modulus 1.5 cm is bulky, which is why founders use insulating sleeves to shrink risers and improve yield.
- ConclusionChvorinov's rule turns "the riser must freeze last" into a diameter. Undersize it and shrinkage porosity moves into the part; oversize it and metal yield falls.
Worked example 2: gating and fill time
Metal is poured from a sprue 0.20 m tall into a 1200 cm³ mould cavity through a gate of 400 mm² area. Find the velocity at the gate and the time to fill the cavity.
- ProblemFind the gate velocity and fill time for the mould in Figure 2.
- Given / findh = 0.20 m, gate A = 400 mm² = 4.0×10⁻⁴ m², cavity V = 1200 cm³ = 1.2×10⁻³ m³. Find v and the fill time.
- AssumptionsFrictionless Bernoulli flow from the sprue top, steady filling, gate runs full.
- ModelVelocity from Bernoulli, flow rate from continuity, fill time from cavity volume over flow rate.
- Equationsv = √(2gh) Q = Av tfill = V/Q
- Solvev = √(2 × 9.81 × 0.20) = √3.92 = 1.98 m/s. Q = 4.0×10⁻⁴ × 1.98 = 7.92×10⁻⁴ m³/s. tfill = 1.2×10⁻³/7.92×10⁻⁴ = 1.5 s.
- CheckAbout 1.5 s to fill 1.2 litres is plausible for a small casting. A taller sprue would raise v and shorten the fill but risk turbulence and air entrapment, the trade-off behind gating design.
- ConclusionGating is the fluid mechanics of casting: enough head to fill before freezing, but smooth enough to avoid defects. Bernoulli and continuity are all it takes to size a gate.
Misconceptions and diagnostics
| Mistake | Symptom | Diagnostic question | Correction |
|---|---|---|---|
| Ignoring shrinkage | Porosity or sink in the thick section | "Where does the last metal freeze?" | Feed the slowest-freezing region with a riser of larger modulus. |
| Undersized riser | Shrinkage cavity ends up in the part | "Does the riser freeze after the casting?" | Make (V/A)riser > (V/A)casting. |
| Time scales with size, not V/A | Solidification time mis-estimated | "Did I use (V/A)², not volume?" | Chvorinov's rule depends on the modulus squared. |
| Pattern equals part size | Casting comes out undersized | "Did I add the shrinkage allowance?" | Oversize the pattern for solid contraction. |
Practice ladder
A cube of side 8 cm solidifies in a mould with Cm = 2.5 min/cm². Find its solidification time.
Show answer
V/A = (8³)/(6 × 8²) = 512/384 = 1.333 cm. ts = 2.5 × 1.333² = 4.4 min. The modulus, not the side length, sets the time.
A sphere and a cube have the same volume. Which solidifies more slowly, and why?
Show answer
The sphere: it has the least surface area for a given volume, so the highest V/A and the longest Chvorinov time. This is why hot-spots and shrinkage concentrate in compact, rounded sections.
A casting needs a final length of 300 mm in an alloy with 1.6% total solid shrinkage. Find the pattern length, ignoring machining allowance.
Show answer
Pattern length = 300 × (1 + 0.016) = 304.8 mm. The pattern is made oversize so the part shrinks to size on cooling, the role of a shrink rule.
Find a real cast part (an engine block, a manhole cover, a faucet). Identify likely hot spots from the geometry and where you would place risers and gates.
What good work looks like
The thickest, most compact sections flagged as high-modulus hot spots, risers placed to freeze last there, and gates sized to fill before freezing.
Working with AI, and proving it yourself
Use AI as an examiner, not a solver
Portfolio task
Analyse one casting: compute its modulus, size a riser with Chvorinov's rule, and estimate the gate velocity and fill time from a chosen sprue height.
Retrieval and spaced review
Closed notes. Answer out loud, then reveal.
1. State Chvorinov's rule.
ts = Cm(V/A)²: solidification time scales with the square of the modulus.
2. What condition must a riser satisfy?
It must freeze after the casting, so (V/A)riser > (V/A)casting.
3. Name the three shrinkage stages.
Liquid contraction, solidification shrinkage, and solid contraction.
4. How do you find gate velocity and fill time?
v = √(2gh) (Bernoulli) and tfill = V/(Av) (continuity).
5. Which casting process gives the finest detail?
Investment casting; sand casting is the roughest but cheapest.
Textbook mapping
| Item | Mapping |
|---|---|
| Primary source | Kalpakjian and Schmid, Manufacturing Engineering and Technology, Chapters 10 to 12 (Metal Casting) |
| Cross-reference | Groover, Ch. 10 and 11 · DeGarmo, casting chapters |
| Core topics | 2.1 Solidification and shrinkage · 2.2 Chvorinov's rule · 2.3 Risers · 2.4 Gating · 2.5 Casting processes |
| Engineering connection | Engine blocks, housings, and investment-cast turbine blades. |
| Read next | Chapter 3: Bulk Deformation. |