Fluid Mechanics · Chapter 2 of 10 · Beginner
Properties of Fluids
Density, viscosity, vapor pressure, surface tension: a handful of properties set how a fluid resists flow, when it boils, and how it climbs a tube. Get them right and every later calculation follows.
Readiness check
This chapter quantifies the fluid properties. Tick only what you can do closed-notes.
- Recall density ρ and its units.
- Compute a gradient (rate of change with distance).
- Use force = stress × area.
- Recall that liquids boil when pressure meets vapor pressure.
- Look up a property at a stated temperature.
The core idea
Viscosity is the property that resists flow: the shear stress is proportional to the velocity gradient, τ = μ(du/dy). Density, vapor pressure, and surface tension complete the picture.
τ = μ (du/dy)ν = μ/ρ, SG = ρ/ρwatercapillary: h = 2σcosθ/(ρgr)A fluid's resistance to shear is its viscosity μ; Newton's law of viscosity says the shear stress equals μ times the velocity gradient across the flow. Dividing by density gives the kinematic viscosity ν that appears in the Reynolds number. Two more properties matter at boundaries: vapor pressure sets when a liquid cavitates (boils due to low pressure), and surface tension drives capillary rise and droplet behaviour. Liquids are nearly incompressible; gases are not.
The skills, taught in order
Five properties carry through the whole course: density, viscosity, vapor pressure, surface tension, and compressibility.
2.1 Density and specific gravity
Density ρ is mass per volume; specific weight is γ = ρg; specific gravity SG = ρ/ρwater is the dimensionless ratio to water (1000 kg/m³). Liquid density barely changes with pressure, but gas density follows the ideal-gas law, ρ = P/(RT).
2.2 Viscosity
Viscosity measures resistance to shear. Newton's law of viscosity, τ = μ(du/dy), relates the shear stress to the velocity gradient, with μ the dynamic viscosity (Pa·s). The kinematic viscosity is ν = μ/ρ (m²/s). Newtonian fluids (water, air, oil) have constant μ; others thin or thicken with shear rate. Liquid viscosity falls with temperature; gas viscosity rises.
2.3 Vapor pressure and cavitation
The vapor pressure Pv is the pressure at which a liquid boils at a given temperature. If the local pressure in a flow drops to Pv (say at a pump inlet or propeller tip), vapor bubbles form and collapse violently, called cavitation, which erodes metal and must be avoided.
2.4 Surface tension and capillarity
Surface tension σ (N/m) is the energy of a liquid surface, responsible for droplets and bubbles. In a small tube it drives capillary rise h = 2σcosθ/(ρgr), where θ is the contact angle and r the tube radius. The effect grows as the tube narrows.
2.5 Compressibility
The bulk modulus Ev = −dP/(dV/V) measures resistance to volume change. For water it is about 2.2 GPa, so liquids are treated as incompressible. Gases compress easily, but a gas flow is still treated as incompressible when its Mach number is below about 0.3.
| Property (at 20 °C) | Water | Air (1 atm) |
|---|---|---|
| Density ρ (kg/m³) | 998 | 1.20 |
| Dynamic viscosity μ (Pa·s) | 1.00×10⁻³ | 1.82×10⁻⁵ |
| Kinematic viscosity ν (m²/s) | 1.00×10⁻⁶ | 1.52×10⁻⁵ |
| Vapor pressure / surface tension | 2.34 kPa / 0.0728 N/m | n/a (gas) |
Engineering connection: viscosity sets pipe friction and drag, vapor pressure limits pump suction, and surface tension matters in small channels, sprays, and coatings.
Worked example 1: viscous drag on a plate
A 0.3 m × 0.3 m plate slides at 1 m/s over a 1 mm thick film of oil (μ = 0.8 Pa·s) on a fixed surface. Find the shear stress and the force needed to move the plate.
- ProblemFind the shear stress and driving force for the plate in Figure 1.
- Given / findA = 0.3 × 0.3 m², V = 1 m/s, h = 0.001 m, μ = 0.8 Pa·s. Find τ and F.
- AssumptionsNewtonian oil, linear velocity profile across the thin film, no-slip at both surfaces.
- ModelNewton's law with a linear gradient du/dy = V/h, then F = τA.
- Equationsτ = μ(du/dy) = μV/h F = τA
- Solveτ = 0.8 × (1/0.001) = 800 Pa. A = 0.09 m², so F = 800 × 0.09 = 72 N.
- CheckUnits: (Pa·s)(1/s) = Pa for τ, and Pa·m² = N for F. A thinner film (smaller h) would raise both, which is why bearings run on very thin, low-viscosity films to limit drag.
- ConclusionThe whole resistance comes from viscosity acting across the velocity gradient. This is the model behind lubrication, journal bearings, and viscometers.
Worked example 2: capillary rise
A clean glass tube of 1 mm diameter stands in water at 20 °C (σ = 0.0728 N/m, ρ = 998 kg/m³, contact angle ≈ 0°). How high does the water rise in the tube?
- ProblemFind the capillary rise of water in the tube in Figure 2.
- Given / findd = 1 mm so r = 0.5 mm, σ = 0.0728 N/m, ρ = 998 kg/m³, θ ≈ 0°. Find h.
- AssumptionsClean tube (θ = 0, fully wetting), water at 20 °C, static column.
- ModelBalance the surface-tension pull around the rim against the weight of the raised column.
- Equationsh = 2σcosθ/(ρgr)
- Solveh = (2 × 0.0728 × cos 0°)/(998 × 9.81 × 0.0005) = 0.1456/4.895 = 0.0297 m = 29.7 mm.
- CheckThe rise is inversely proportional to radius, so a 0.5 mm tube would lift water about 59 mm. This is why capillary effects dominate in thin tubes and porous media but are invisible in a wide beaker.
- ConclusionSurface tension produces measurable rise only at small scales. It matters in micro-channels, wicks, and soils, and is negligible in ordinary pipes.
Misconceptions and diagnostics
| Mistake | Symptom | Diagnostic question | Correction |
|---|---|---|---|
| Confusing μ and ρ | Reynolds number or drag wrong | "Is this resistance to shear or mass per volume?" | μ is viscosity (Pa·s); ρ is density (kg/m³); ν = μ/ρ links them. |
| Ignoring temperature | Wrong viscosity used | "At what temperature is this property?" | Always read properties at the stated temperature. |
| Forgetting cavitation | Pump or valve erodes | "Does local pressure drop to Pv?" | Keep the local pressure above the vapor pressure. |
| Capillarity at large scale | Surface tension included in a wide pipe | "How small is the length scale?" | Capillary rise scales as 1/r; negligible in ordinary pipes. |
Practice ladder
Oil (μ = 0.25 Pa·s) fills a 2 mm gap; the upper plate moves at 0.5 m/s. Find the shear stress.
Show answer
τ = μV/h = 0.25 × (0.5/0.002) = 0.25 × 250 = 62.5 Pa.
A fluid has SG = 0.85 and ν = 5×10⁻⁵ m²/s. Find its density and dynamic viscosity.
Show answer
ρ = SG × 1000 = 850 kg/m³. μ = ρν = 850 × 5×10⁻⁵ = 0.0425 Pa·s.
Water at 20 °C flows through a region where the pressure drops to 2 kPa absolute. Does it cavitate?
Show answer
The vapor pressure of water at 20 °C is 2.34 kPa. Since the local pressure (2 kPa) is below Pv, the water boils locally: yes, it cavitates. Keeping pressure above 2.34 kPa would prevent it.
Find a real situation where one of these properties dominates (oil viscosity in a cold engine, cavitation on a propeller, capillary action in a paper towel). Estimate the relevant property and its effect.
What good work looks like
The governing property identified and read at the right temperature, a quantitative estimate (shear stress, vapor-pressure margin, or capillary rise), and a clear physical consequence.
Working with AI, and proving it yourself
Use AI as an examiner, not a solver
Portfolio task
Measure or estimate one fluid property in a real setting: a viscous drag, a cavitation margin, or a capillary rise, with the property read at the correct temperature.
Retrieval and spaced review
Closed notes. Answer out loud, then reveal.
1. Write Newton's law of viscosity.
τ = μ(du/dy): shear stress equals viscosity times the velocity gradient.
2. Relate dynamic and kinematic viscosity.
ν = μ/ρ (m²/s); ν appears in the Reynolds number.
3. What is cavitation?
Local boiling when the pressure drops to the vapor pressure; the bubbles collapse and erode surfaces.
4. Give the capillary-rise formula.
h = 2σcosθ/(ρgr); the rise grows as the tube narrows.
5. When can a gas flow be treated as incompressible?
When the Mach number is below about 0.3.
Textbook mapping
| Item | Mapping |
|---|---|
| Primary source | Çengel and Cimbala, Fluid Mechanics: Fundamentals and Applications, Chapter 2 (Properties of Fluids) |
| Cross-reference | White, Ch. 1 · Munson, Ch. 1 |
| Core topics | 2.1 Density · 2.2 Viscosity · 2.3 Vapor pressure and cavitation · 2.4 Surface tension · 2.5 Compressibility |
| Engineering connection | Lubrication, pump cavitation limits, sprays, and micro-channels. |
| Read next | Chapter 3: Pressure and Fluid Statics. |